Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and immediately invoke it. 16 Mar 2015 A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and�
Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the
Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and immediately invoke it. 16 Mar 2015 A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and�
Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the
Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and immediately invoke it. 16 Mar 2015 A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and�
16 Mar 2015 A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and�
Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and immediately invoke it.
A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and immediately invoke it.
Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the Seriously, I can't figure this out. The documentation gives us: stub.callsArg(index) - Causes the stub to call the argument at the provided index as a callback function. stub.callsArg(0); causes the A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and immediately invoke it. 16 Mar 2015 A stub is a noop function with programmable behavior. In your case callsArg( index) will program the stub to expect a function at index and�